LeetCode in TypeScript
739. Daily Temperatures
Medium
Given an array of integers temperatures represents the daily temperatures, return an array answer such that answer[i] is the number of days you have to wait after the ith day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0 instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73]
Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60]
Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90]
Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 10530 <= temperatures[i] <= 100
Solution
function dailyTemperatures(temperatures: number[]): number[] {
let stack: number[] = []
let result: number[] = new Array(temperatures.length).fill(0)
for (let i = 0; i < temperatures.length; i++) {
while (stack.length && temperatures[i] > temperatures[stack[stack.length - 1]]) {
let index: number | undefined = stack.pop()
result[index!] = i - index!
}
stack.push(i)
}
return result
}
export { dailyTemperatures }