Medium
Given an array of integers nums
containing n + 1
integers where each integer is in the range [1, n]
inclusive.
There is only one repeated number in nums
, return this repeated number.
You must solve the problem without modifying the array nums
and uses only constant extra space.
Example 1:
Input: nums = [1,3,4,2,2]
Output: 2
Example 2:
Input: nums = [3,1,3,4,2]
Output: 3
Example 3:
Input: nums = [1,1]
Output: 1
Example 4:
Input: nums = [1,1,2]
Output: 1
Constraints:
1 <= n <= 105
nums.length == n + 1
1 <= nums[i] <= n
nums
appear only once except for precisely one integer which appears two or more times.Follow up:
nums
?function findDuplicate(nums: number[]): number {
const arr: number[] = new Array(nums.length + 1).fill(0)
for (const num of nums) {
arr[num] += 1
if (arr[num] === 2) {
return num
}
}
return 0
}
export { findDuplicate }