Easy
Given two strings s
and t
, return true
if t
is an anagram of s
, and false
otherwise.
Example 1:
Input: s = “anagram”, t = “nagaram”
Output: true
Example 2:
Input: s = “rat”, t = “car”
Output: false
Constraints:
1 <= s.length, t.length <= 5 * 104
s
and t
consist of lowercase English letters.Follow up: What if the inputs contain Unicode characters? How would you adapt your solution to such a case?
function isAnagram(s: string, t: string): boolean {
if (s.length !== t.length) {
return false
}
let counts = new Array(26).fill(0)
for (let i = 0; i < s.length; ++i) {
counts[s.charCodeAt(i) - 'a'.charCodeAt(0)]++
counts[t.charCodeAt(i) - 'a'.charCodeAt(0)]--
}
return counts.every((c) => c === 0)
}
export { isAnagram }