Medium
Given an integer array nums
, return an array answer
such that answer[i]
is equal to the product of all the elements of nums
except nums[i]
.
The product of any prefix or suffix of nums
is guaranteed to fit in a 32-bit integer.
You must write an algorithm that runs in O(n)
time and without using the division operation.
Example 1:
Input: nums = [1,2,3,4]
Output: [24,12,8,6]
Example 2:
Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]
Constraints:
2 <= nums.length <= 105
-30 <= nums[i] <= 30
nums
is guaranteed to fit in a 32-bit integer.Follow up: Can you solve the problem in O(1)
extra space complexity? (The output array does not count as extra space for space complexity analysis.)
function productExceptSelf(nums: number[]): number[] {
const n = nums.length
const ans: number[] = new Array(n)
let product = 1
// Calculate the product of all elements to the left of each element
for (let i = 0; i < n; i++) {
ans[i] = product
product *= nums[i]
}
product = 1
// Calculate the product of all elements to the right of each element
for (let i = n - 1; i >= 0; i--) {
ans[i] *= product
product *= nums[i]
}
return ans
}
export { productExceptSelf }