Easy
Given an integer array nums and an integer k, return true if there are two distinct indices i and j in the array such that nums[i] == nums[j] and abs(i - j) <= k.
Example 1:
Input: nums = [1,2,3,1], k = 3
Output: true
Example 2:
Input: nums = [1,0,1,1], k = 1
Output: true
Example 3:
Input: nums = [1,2,3,1,2,3], k = 2
Output: false
Constraints:
1 <= nums.length <= 105-109 <= nums[i] <= 1090 <= k <= 105function containsNearbyDuplicate(nums: number[], k: number): boolean {
const s = new Set()
for (let i = 0, l = nums.length; i < l; i++) {
if (i > k) {
s.delete(nums[i - k - 1])
}
if (s.has(nums[i])) {
return true
}
s.add(nums[i])
}
return false
}
export { containsNearbyDuplicate }